Using replace with two variables

[tut]

In my configuration file, I have this code–

copyright  = "© 2019-{year}"

Which works with this code in the footer–

{{ replace site.Copyright "{year}" (string (now.Format "2006") )

I want now to add the code below with {title} representing site.Title –

copyright = "© 2019-{year} {title}"

I need help with editing the code above in the footer to show both the year and the date.

[gaetawoo]

Just nest the replaces… one replace statement becomes the input to the other replace statement

[tut]

An example?

[davidsneighbour]

{{ $footerline := replace site.Copyright "{year}" (string (now.Format "2006")) }}
{{ $footerline = $footerline | replace "{title}" site.Title }}

First line replaces the {year} in site.Copyright with the current year and sets $footerline to that replaced string. Second line “pipes” $footerline into the replace function (this replaces the first parameter) and replaces {title} with site.Title.

Note the := on the first line - you initiate the variable - and the = in the subsequent line (and all that might follow) - you change the variable.

This should work, but I didn’t test it.

[tut]

@davidsneighbour

This should work

Outputs {title} as the result.

[gaetawoo]

Because you can’t pipe outputs into replace.

Do something like this

{{ replace (replace site.Copyright "{year}" (now.Format "2006")) "{title}" site.Title }}

[tut]

Awesome!