Range over dictionary always sorts

support
1

When using range and a dictionary, I always seem to get results in a case-sensitive sort by key. An answer on StackOverflow seems to indicate that go iterates maps in a random order. Is there a method to make range return dictionary elements in their original, unsorted order?

        {{- $map_test := dict
                "Key 99" "Value 99"
                "Key 2" "Value 2"
                "Key 1" "Value 1"
                "Key 3" "Value 3"
                "key 1" "Value 1 (lowercase)"
        -}}

        {{ range $key, $value := $map_test }}
                <li>{{ $key }}: {{ $value }}</li>
        {{ end }}

The above returns:

  • Key 1: Value 1
  • Key 2: Value 2
  • Key 3: Value 3
  • Key 99: Value 99
  • key 1: Value 1 (lowercase)
2

No, there is not.

https://pkg.go.dev/text/template#hdr-Actions

{{range pipeline}} T1 {{end}}

The value of the pipeline must be an array, slice, map, or channel. If the value of the pipeline has length zero, nothing is output; otherwise, dot is set to the successive elements of the array, slice, or map and T1 is executed. If the value is a map and the keys are of basic type with a defined order, the elements will be visited in sorted key order.

3

Okie doke. That seems strange, coming from other languages! How would one typically handle this use case in go?

4

Perhaps you can restructure your data as an array of maps.

5

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