How to obtain URL prefix with "replaceRE" function?

support
1

Greetings, can anyone explain the correct way to extract the URI “scheme” prefix from a URL? (string before ://)

For example, how would you obtain the prefix string irc from irc://irc.freenode.net/hugo and apt from apt://hugo

Many thanks in advance.

2

The split template function could make your life a bit easier. Try the following:

{{ index (split $url "://") 0 }}

Replace $url with the url from which you would like to obtain the url prefix.

1 Like
3

Hi DC, appreciate the swift response.

Your example works perfectly and far simpler than originally thought (“replaceRE”), the missing ingredient was the “index” function for reading the array output many other Go/Hugo functions return.

Many thanks again!