Finding the last element in an array?

support
1

I have this code:

{{ if ne $element (last 1 $items) }} •{{ end }}

that I thought would output • if the loop around it had more $items to process. But it outputs • regardless.

How am I using this wrong?

2

When passed a slice, the collections.First and collections.Last functions return a slice of the first or last N items, even if N is 1.

Do this instead:

{{ $s := slice "a" "b" "c" "d" }}
{{ range $k, $v := $s }}
  {{ if lt $k (sub (len $s) 1) }}
    THERE'S MORE
  {{ end }}
{{ end }}
3

That’s just what I needed. Thanks. Sometimes Go Templates are hard. :wink:

4

that one should also do

  {{ $collection := slice 1 2 3 4 5}}
  {{ if ne 4 (index (last 1 $collection) 0) }}
    {{ warnf "not 4" }}
  {{ else }}
    {{ warnf "is 4" }}
  {{ end }}
5

I’ve added a couple of dirt simple examples to the documentation, but I would have thought this was sufficient:

Returns the given collection, limited to the last N elements.

6

maybe the return value in the docs could be slice of any or any[]… just an idea.

dunno if index slice -1 for adressing from end of the slice could be a valuable addition.

7

As shown in examples, it can return a string as well.

8

oops. missed that.

then a string is a collection

collections.Last N COLLECTION

9

https://go.dev/blog/strings#what-is-a-string

In Go, a string is in effect a read-only slice of bytes.

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10

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