# Getting title for an alternate output format
**URL:** https://discourse.gohugo.io/t/getting-title-for-an-alternate-output-format/18542
**Category:** support
**Created:** [May 6, 2019, 5:34pm UTC](https://discourse.gohugo.io/t/getting-title-for-an-alternate-output-format/18542 "2019-05-06T17:34:36Z")
**Posts on this page:** 3
**Page:** 1
I would like the RSS feed links on my site to include a title. I tried adding a feed link like this:
```
{{ with .OutputFormats.Get "RSS" }}
{{ end }}
```
This fails with several errors along the lines of:
> ERROR 2019/05/06 13:30:49 render of “section” failed: execute of template failed: template: post/list.html:1:3: executing “post/list.html” at \: error calling partial: “/…/themes/ghostwriter/layouts/partials/header.html:30:24”: execute of template failed: template: partials/header.html:30:24: executing “partials/header.html” at \<.Title\>: can’t evaluate field Title in type \*page.OutputFormat
I thought maybe this was just a question of `.Title` being unset in some contest, so I tried this instead:
```auto
title="{{ .Title | default "" }}">
```
…but that resulted in the same errors. How do I get the page title into this link?
---
Hey there,
An Output Formats retrieve with `.OutputFormats.Get` is an Output Format, `.Title` is available on pages, not on Output Format.
If your page is the root context of your template file then try `$.Title` instead.
---